A point charge q is placed at one of the vertices. FIGURE 15-1 shown in Fig.

A point charge q is placed at one of the vertices. . To find the electric flux flowing through a cube when a point charge Q is placed at one of its vertices, we can use Gauss's Law. Since the cube has eight vertices, only a fraction of the charge contributes to the flux through the cube. Solution: In this case by placing three at three sides of given cube and four cube above, the charge will be in the centre. So, the flux linked with each case will be one-eight of the flux ε0Q Flux associated with given cube = 8ε0Q In this scenario, the charge $$Q$$Q is located at one vertex of the cube. Here’s a step-by-step solution: There are 2 steps to solve this one. 15-1, a point charge of +Q is placed at the centroid of an equilateral triangle. To find the electric flux through the cube when a point charge Q is placed at one of its vertices, we can use Gauss's Law, which states that the electric flux ΦE through a closed surface is given by the equation: ΦE = ε0Qenc where Qenc is the charge enclosed by the surface and ε0 is the permittivity of free space. To find the electric flux flowing through a cube when a point charge Q is placed at one of its vertices, we can use Gauss's Law. Therefore, the charge enclosed by the surface ABCD is only 8q . FIGURE 15-1 shown in Fig. If we consider the charge q placed at one vertex, it is shared equally among 8 cubes that could be formed by extending the cube in all directions. adng knb ddng pfh ijk ernkdl ofx ysitcyoq rnskull xay